Q: 10 years ago the average age of a family of 4 members was 24 years.Since then,two children having been born , still the average age of the family is the same today If the two children differ in age by 2 years,find the present age of the younger child? [S.S.C.2007]

Answer: B

Explanation:

Solution

Total age 4 members,10 years ago=(24×4)=96

Total age of 4 members now=(98+10×4)=136

Total age of 6 members now=(24×6)=144

Sum of the ages of 2 children=(144-136)=8 years

Let the age of the younger child be x years

Then the age of the elder child=(x+2)

so,. x+x+2=8

2x=6. x=3

Age of the younger child=3 years