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Q10 years ago the average age of a family of 4 members was 24 years.Since then,two children having been born , still the average age of the family is the same today If the two children differ in age by 2 years,find the present age of the younger child?
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Correct Answer: Option B
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Total age 4 members,10 years ago=(24×4)=96
Total age of 4 members now=(98+10×4)=136
Total age of 6 members now=(24×6)=144
Sum of the ages of 2 children=(144-136)=8 years
Let the age of the younger child be x years
Then the age of the elder child=(x+2)
so,. x+x+2=8
2x=6. x=3
Age of the younger child=3 years
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