Arithmetic Aptitudes › Problems on Ages › Question #4388
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QThe ratio of the ages of a father and his son is 17:7 respectively. Six years ago, the ratio of their ages was 3: 1 respectively. What is the father's present age?

ID: #4388 Problems on Ages 285 views
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#4388Q ID
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Problems on AgesTopic
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  • A 64 years ✔ ✖
  • B 51 years ✔ ✖
  • C 48 years ✔ ✖
  • D Can't be determined. ✔ ✖
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Explanation

Let the present ages of the father and son be 17x and 7x years respectively. Six years ago, the ages of the father and son were (17x - 6) and (7x - 6) years respectively. The ratio of their ages six years ago was (17x - 6) : (7x - 6) = 3:1. Solving this equation for x, we get x = 3 Substituting this value in the expression for the father's present age, we get that the father's present age is 17 * 3 = 51years.

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