Arithmetic Aptitudes › Problems on Ages › Question #4408
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QTen years ago, the mother's age was three times the age of her son. In ten years, the mother's age will be twice the age of her son. What is the ratio of their ages now?

ID: #4408 Problems on Ages 142 views
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#4408Q ID
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Problems on AgesTopic
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  • A 11:7 ✔ ✖
  • B 7:4 ✔ ✖
  • C 7:3 ✔ ✖
  • D 9:5 ✔ ✖
Correct Answer: Option C

Explanation

Ten years ago:

Mother's age = 3x
Son's age = x
At present:

Mother's age = 3x + 10
Son's age = x + 10
After ten years:

Mother's age = (3x + 10) + 10 = 3x + 20
Son's age = (x + 10) + 10 = x + 20
Mother's age is twice that of son after ten years:
3x + 20 = 2(x + 20)

Solving the equation:
3x + 20 = 2x + 40
x = 20

The present age ratio of the mother to the son is:
(3x + 10) : (x + 10) = 7:3

The mother is currently 70 years old and the son is currently 30 years old
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