Arithmetic Aptitudes › Problems on Ages › Question #4419
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QTen years ago, John's age was three times the age of his son. In ten years, John's age will be twice that of his son. What is the ratio of their current ages?

ID: #4419 Problems on Ages 300 views
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#4419Q ID
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Problems on AgesTopic
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  • A 7:3 ✔ ✖
  • B 3:7 ✔ ✖
  • C 9:4 ✔ ✖
  • D 4:9 ✔ ✖
Correct Answer

Explanation

x: age of son 10 years ago

3x: age of John 10 years ago  




2(x+20) = 3x+20: in 10 years, John's age will be twice that of the son's age 


x+10: present age of son 


3x+10: present age of John 


x+10 = 30: present age of son is 30 years old 


3x+10 = 70: present age of John is 70 years old 


x = 20: age of son 10 years ago is 20 years 


3x = 60: age of John 10 years ago is 60 years 


70:30 = 7:3: ratio of present ages of John and son is 7:3

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