Q: Ten years ago, John's age was three times the age of his son. In ten years, John's age will be twice that of his son. What is the ratio of their current ages?

A 7:3
B 3:7
C 9:4
D 4:9

Share this MCQ

Answer: A

Explanation:

x: age of son 10 years ago

3x: age of John 10 years ago  




2(x+20) = 3x+20: in 10 years, John's age will be twice that of the son's age 


x+10: present age of son 


3x+10: present age of John 


x+10 = 30: present age of son is 30 years old 


3x+10 = 70: present age of John is 70 years old 


x = 20: age of son 10 years ago is 20 years 


3x = 60: age of John 10 years ago is 60 years 


70:30 = 7:3: ratio of present ages of John and son is 7:3

Problems on Ages

Share Above MCQ

‹ Previous Next ›

Write your comment

Learn More MCQ Questions from Arithmetic Aptitudes Problems on Ages

Q: Ten years ago, John's age was three times the age of his son. In ten years, John's age will be twice that of his son. What is the ratio of their current ages?

Report Question