General Aptitude Time and Distance Question #4673
Single Choice Not Set

QIn 27 seconds and 17 seconds, two trains travelling in opposing directions cross a guy standing on the platform. What is the ratio of their speeds if they cross in 23 seconds?

ID: #4673 Time and Distance 190 views
Question Info
#4673Q ID
Not SetDifficulty
Time and DistanceTopic

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  • A 3 : 2
  • B 5 : 2
  • C 3 : 8
  • D 3 : 7
Correct Answer

Explanation


The speed of the first train is given as x and the speed of the second train is given as y.

The length of the first train is given as 27x and the length of the second train is given as 17y.

The relative speed of the two trains is given as x + y.

The time taken for the two trains to cross each other is given as 23 seconds.

We can use the lengths of the trains, the relative speed, and the time taken for the trains to cross each other to find the speed ratio between the two trains. Since the time taken for the trains to cross each other is 23 seconds and the relative speed is x + y, we can set up the following equation: (27x + 17y)/(x + y) = 23.

Solving for x, we get x = (6y)/4.

The speed ratio between the two trains is given by the ratio of their speeds, which is x/y. Plugging in the value of x that we found in step 6, we get x/y = (6y)/(4y) = 3/2.

Therefore, the speed ratio between the two trains is 3/2.

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