Q: The age of a man 10 years ago was thrice the age of his son .10 years hence the man's age will be twice the age of his son the ratio of their present age is? [LIC 2003]

Answer: B

Explanation:

Solution

let son's age 10 years ago be x years then man age 10 years ago be 3x years

sons present age equal to (x+10) man's present age=(3x+10)years

(3x+10)+10=2(x+10+10)

3x+20=2(x+20)

3x+20=2x+40

x=20

Problems on Ages

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