✏️ Explanatory Question
Convert:
\[ (1)_{10} \text{ to Binary} \]
\[ \begin{array}{r|l} 2 & 1 \\ \hline & 0 \quad 1 \\ \end{array} \]
Reading remainder from bottom to top:
\[ 1 \]
Therefore,
\[ (1)_{10} = (1)_2 \]
Convert:
\[ (2)_{10} \text{ to Binary} \]
\[ \begin{array}{r|l} 2 & 2 \\ \hline 2 & 1 \quad 0 \\ \hline & 0 \quad 1 \\ \end{array} \]
Reading remainders from bottom to top:
\[ 10 \]
Therefore,
\[ (2)_{10} = (10)_2 \]
Convert:
\[ (3)_{10} \text{ to Binary} \]
\[ \begin{array}{r|l} 2 & 3 \\ \hline 2 & 1 \quad 1 \\ \hline & 0 \quad 1 \\ \end{array} \]
Reading remainders from bottom to top:
\[ 11 \]
Therefore,
\[ (3)_{10} = (11)_2 \]
Convert:
\[ (4)_{10} \text{ to Binary} \]
\[ \begin{array}{r|l} 2 & 4 \\ \hline 2 & 2 \quad 0 \\ \hline 2 & 1 \quad 0 \\ \hline & 0 \quad 1 \\ \end{array} \]
Reading remainders from bottom to top:
\[ 100 \]
Therefore,
\[ (4)_{10} = (100)_2 \]